이항 분포의 평균이
다음 식으로 주어진다는 것을 증명, (이항 분포의 평균은 횟수 * 그 확률)
We note that m = 0 actyakky doesn't affect the Expectation, so we let the summation begin from m = 1,
Moreover, in the second last step, we rewrite the subindex of the summation, and what we actually do is let,
k = m - 1,
And in the last step, we have taken advantage of binomial theorem,
Variance is straightforward once Expectation has been calculated.
Here we will use a little tick, ,
-mu = -1 + (1 - mu)